Answer to Question #110339 in General Chemistry for Madison

Question #110339
Consider the mechanism below:

NO2 + F2 NO2F + F k1, slow

F + NO2 NO2F k2, fast

What is the rate law?
1
Expert's answer
2020-04-19T07:09:55-0400

NO2 + F2 --k1---NO2F + F, slow

F + NO2 ---k2---NO2F , fast

2NO2+F2 ---2NO2F

the 1 step is rate determining

These are bimolecular reactions.

A + B-C. The following expression of the reaction rate is performed for them.

V=CACB

Rate=k1[NO2][F2]


Therefore, the reaction rate for the balancing equation will also be

Rate=k[NO2][F2]


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