Answer to Question #110336 in General Chemistry for anna

Question

n this experiment you will react calcium chloride and sodium carbonate in a double replacement reaction, making a solid precipitate you can filter off.

CaCl2(aq) + Na2CO3(aq) --> CaCO3(s) +2 NaCl(aq)





What is the molar mass of: (0.5 pt. ea.) (whole numbers please)

CaCl2? _______________
CaCO3? ­­­­­­­­­­­­­­­­­­­­­­­­­­______________

Answer 1

Solution:

1) CaCl₂ - calcium chloride

M(CaCl₂) = Ar(Ca) + 2*Ar(Cl) = 40 + 2*35.5 = 111 (g/mol).

M(CaCl₂) = 111 g/mol.

2) CaCO₃ - calcium carbonate

M(CaCO₃) = Ar(Ca) + Ar(C) + 3*Ar(O) = 40 + 12 + 3*16 = 100 (g/mol).

M(CaCO₃) = 100 g/mol.

Answer:

Molar mass of CaCl₂ is 111 g/mol.

Molar mass of CaCO₃ is 100 g/mol.