Solution.
w(C) = 57.14%;
w(H) = 4.80%;
w(O) = 38.06%;
x:y:z =(w(C)/Ar(C)):(w(H)/Ar(H)):(w(O)/Ar(O));
x:y:z = ( 0.5714/12):(0.048/1):(0.3806/16) = 0.0476:0.048:0.0238 = 2:2:1;
It is therefore the simplest formula of an organic compound С2Н2O;
M(C2H2O) = 24+2+16 = 42 amu;
This formula is not true because M(C2H2O) =42 amu , but not 126 amu;
42"\\sdot" a = 126; a = 3;
The compound formula has the form: C6H6O3;
Answer: C6H6O3.
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