In Heme B "9.09" % of Iron is present by mass and it contain only one atom
We know that atomic mass of Iron atom is 55.85
So from this we can take mass of Heme B be x
9.09 % of X = 55.85
"\\frac{9.09 \\times x}{100}=55.85"
x= 614.41 g/mole is the molar mass of Heme B.
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