Question

A gas occupies a volume of 300cm cube at 410mmHg. What will be its pressure when volume is decreased to 130cm cube at constant temperature.

Answer 1

According to the conditions of the question we should make up two equations of Mendeleev-Clapeyron, which characterize the initial and final state for this gas:

$p(1)•V(1) = \nu•R•T$

$p(2)•V(2)=\nu•R•T$

Since the left sides of the equations are equal to one product ($\nu•R•T$), therefore they are equal to each other:

$p(1)•V(1)=p(2)•V(2)$ $\to$ $p(2) = (p(1)•V(1))/V(2)$ = (300(cm³)•410(mmHg))/130(cm³) = 946 mmHg

Answer: p(2)=946 mmHg