If it is a hydrocarbon then it must be of the form "C_xH_y"
As the question says one mole of the hydrocarbon contains 36 g of carbon then it contains 3 moles of carbon which means that the value of x=3
we are given that the vapour density is 20 which means molecular weight is 40 (molecular wight = 2 x vapour density )
we are already given mass of carbon in the compound is 36 which means remaining is of hydrogen which is equal to (40-36)=4g
which means that hydrogen atom will be equal to 4
"C_3H_4"
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Thanks alot it really helped
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