Question

Calculate the mole fraction of HNO3 and water in solution of nitric acid in water containing 45percent of HNO3 by weight

Answer 1

$\alpha(HNO_3)=[w(HNO_3)/M(HNO_3)] :[w(HNO_3)/M(HNO_3)+w(H_2O)/M(H_2O)]$

$α(HNO3​)=[45/63]:[45/63+55/18] =45/63:(45/63+55/18)=0.199$

=19,9% mole fraction