"\\alpha(HNO_3)=[w(HNO_3)\/M(HNO_3)] :[w(HNO_3)\/M(HNO_3)+w(H_2O)\/M(H_2O)]"
"\u03b1(HNO3\u200b)=[45\/63]:[45\/63+55\/18] =45\/63:(45\/63+55\/18)=0.199"
=19,9% mole fraction
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