This problem is similar to geometric progression where the initial amount is 50 and the common ratio is 0.5 which is the dilution factor
after 5 dilution the concentration will be 2550=3250
concentration in 1 st tube will be 50×21
concentration in 2nd tube will be 50×21×21
concentration in 3rd tube will be 50×21×21×21
concentration in 4th tube will be 50×21×21×21×21
concentration in 5th tube will be 50×21×21×21×21×21
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