molar heat of fusion, Q=N∗C∗δTQ=N*C*\delta TQ=N∗C∗δT
N=m/RMMN=m/RMMN=m/RMM
N=115/18=6.388moles
Q=6.388*4200*(105--15)=3219552J
Q=3219.55kJ
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