n(CaO) = "{\\frac {3.50} {56}}=0.0625" mol
for reaction with this amount of CaO the same amount of H2O needed
n(H2O) reacted = 0.0625 mol
m(H2O) reacted = 0.0625*18 = 1.125 g
m(H2O) remained = 3.38 - 1.125 = 2.255 g
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