Answer to Question #108625 in General Chemistry for billy

Question

Calculate the molarity of a solution made of 200.29 grams of sodium nitrate if dissolved in 1.75 liters of water.

Answer 1

Solution.

The Mol. mass of sodium nitrate is 82.0343gm/M.

Since 84.9947 gm sodium nitrate in 1000 ml of water is equal to 1 M molarity.

200.29  gm dissolved in 1750 ml of water, 

hence

(200.29/1750)$\sdot$ (1000/84.9947)=1.347 M;

Molarity of solution is 1.347 M.

Answer: Molarity of solution is 1.347 M.