Question #108340
A reading reports that the amount of Cl present in a local swimming pool is 1.8g. If it contains 600,000g of solution, what is the concentration of Cl in parts per million?
1
Expert's answer
2020-04-07T13:48:13-0400

Solution.

w(Cl)=m(Cl)m(sol)w(Cl) = \frac{m(Cl)}{m(sol)}

w(Cl)=1.8600,000=3 ppmw(Cl) = \frac{1.8}{600,000} = 3 \ ppm

Answer:

w(Cl) = 3 ppm


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