Question #108241
Consider the following half reaction:
Na⁺(aq) + e⁻ → Na(s).
For this reaction, E°(red) = -2.7 V. If this reaction is tripled so that 3 Na⁺ ions are reduced to 3 Na atoms, what is the new E°(red)?
Na⁺(aq) + e⁻ → Na(s).
For this reaction, E°(red) = -2.7 V. If this reaction is tripled so that 3 Na⁺ ions are reduced to 3 Na atoms, what is the new E°(red)?
Expert's answer
When adding up the electrode reactions, the potentials are added algebraically and their sum will be the electromotive force of the total reaction of the galvanic element.
Because ,E°(Na+/Na) = -2.7 V.
Na⁺(aq) + e⁻ → Na(s). x3
=>-2.7*3=-8.1
