Answer to Question #108016 in General Chemistry for Elle

Question

Consider the reaction 3CaCl2(aq) + 2Na3PO4(aq) --> Ca3(PO4)2(s) + 6 NaCl(aq) (molar mass of calcium phosphate is 310.18 g/mol)

What mass of Ca3(PO4)2 is produced from 94.2 mL of 0.250 M Na3PO4 solution?

Answer 1

3CaCl₂(aq) + 2Na₃PO₄(aq) -> Ca₃(PO₄)₂(s) + 6NaCl(aq)

n(Na₃PO₄) = 0.25*0.0942 = 0.02355 mol

n(Ca₃(PO₄)₂) = n(Na₃PO₄)/2 = 0.02355/2 = 0.011775 mol

m(Ca₃(PO₄)₂) = 0.011775*310.18 = 3.6524 g