"2H_2S(g) \\leftrightarrow 2H_2(g) + S_2(g)"
Make ICE table
"[H_2S]" "[H_2]" "[S_2]"
Initial 3.60 0 0
Change -x +x +0.5x
Equilibrium 3.60-x x 0.5 x
"K_c = \\frac{[H_2]^2[S_2]}{[H_2S]^2}"
"2.2\\times 10^{-4} = \\frac{(x^2)(0.5x)}{(3.60-x)^2}"
make an assumption that 3.60-x = 3.60
"2.2\\times10^{-4} = \\frac{(x^2)(0.5x)}{(3.60)^2}"
"x=0.179"
"[H_2S] = 3.6-0.179 = 3.421 M"
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