Question #108013
1. The value of KC for the thermal decomposition of hydrogen sulfide, shown below, is 2.2 × 10-4 at 1400 K.
2H2S(g) ⇌ 2H2(g)+ S2(g)
A sample of gas in which [H2S] = 3.60 M is heated to 1400 K in a sealed vessel. After chemical equilibrium has been achieved, what is the value of [H2S]? Assume no H2 or S2 was present in the original sample. answer in M
1
Expert's answer
2020-04-06T11:48:22-0400

2H2S(g)2H2(g)+S2(g)2H_2S(g) \leftrightarrow 2H_2(g) + S_2(g)

Make ICE table

[H2S][H_2S] [H2][H_2] [S2][S_2]

Initial 3.60 0 0

Change -x +x +0.5x

Equilibrium 3.60-x x 0.5 x


Kc=[H2]2[S2][H2S]2K_c = \frac{[H_2]^2[S_2]}{[H_2S]^2}


2.2×104=(x2)(0.5x)(3.60x)22.2\times 10^{-4} = \frac{(x^2)(0.5x)}{(3.60-x)^2}


make an assumption that 3.60-x = 3.60


2.2×104=(x2)(0.5x)(3.60)22.2\times10^{-4} = \frac{(x^2)(0.5x)}{(3.60)^2}


x=0.179x=0.179


[H2S]=3.60.179=3.421M[H_2S] = 3.6-0.179 = 3.421 M


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