Question

What temperature would a 2m water solution of CaCl2 boil at?

Kb water is .52 BP water is 100oC ATb = (i)(kb)(m)

Answer 1

Elevation in boiling point of the solution$(\triangle T)= K_b m$ $=0.52\times 2=1.04\degree C$

The new boiling point will be$\ 100+1.04= 101.04\degree C$