Answer to Question #107561 in General Chemistry for Yasmin

Question

50cm3 of nitrogen gas combine with 150cm3 of hydrogen gas to form 100cm3 of ammonia. Are these experimental facts in keeping with Gay Lussacs law of combining volumes?

Answer 1

   N_2(g) + 3H_2(g) = 2NH_3(g)

1 mole of nitrogen gas combines with 3 mols of hydrogen gas to form 2 mol of a ammonia gas.

1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia

e.g. what volume of hydrogen reacts with 50 cm³ nitrogen and what volume of ammonia will be formed?

The mole ratio is 1 : 3 =2,

so you multiply equation ratio numbers by 50 giving

50 cm³ nitrogen + 150 cm³ hydrogen (3 x 50) ==> 100 cm³ of ammonia (2 x 50)

These experimental facts are keeping with Gay Lussacs law of combining volumes