Question

Na2CO3 + Ca(OH)2--> CaCO3 + 2NAOH If the chemist mixes 75 ml of 1.5M Ca(OH)2, how many grams of NaOH will be produced?

Answer 1

$n=C*V$

$n$ $(Ca(OH)_2)=1.5М*0.075L=0.1125mol$

The chemical reaction equation shows that sodium hydroxide is formed twice as much as calcium hydroxide reacts.

$n(NaOH)=0.1125mol*2=0.225 mol$

$m=n*M$

$m(NaOH)=0.225 mol*40g/mol=9g$

The answer is 9 grams of NaOH