Answer to Question #107157 in General Chemistry for Brenda Lustre

Question #107157

How many atoms are in
117
g
of calcium?

Expert's answer

Hello

N(Ca)=n(Ca)*N_A

N_A=6.02*10²³

n(Ca)=m(Ca)/M(Ca)=117/40=2.925mole

N(Ca)=2.925*6.02*10²³=17.609*10²³atoms

Answer - 17.609*10²³atoms

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