The aluminum (II) oxide is an interesting substance detected in stellar absorption spectra. Since the molar mass of aluminum is 27 g/mol and the molar mass of atomic oxygen is 16 g/mol, we can calculate what portion of mass accounts for aluminum:
ω(Al)=M(AlO)M(Al). Therefore, the mass of aluminum contained in 510 g of the oxide is
m(Al)=ω(Al)m(AlO)=M(AlO)M(Al)m(AlO)= =27+1627⋅510=320 g.
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