Answer to Question #106447 in General Chemistry for Mila

Question

Calculate how many grams of aluminum are contained in 510 grams Al O

Answer 1

The aluminum (II) oxide is an interesting substance detected in stellar absorption spectra. Since the molar mass of aluminum is 27 g/mol and the molar mass of atomic oxygen is 16 g/mol, we can calculate what portion of mass accounts for aluminum:

$$\omega(\text{Al})=\frac{\Mu(\text{Al})}{\Mu(\text{AlO})}.$$

Therefore, the mass of aluminum contained in 510 g of the oxide is

$$m(\text{Al})=\omega(\text{Al})m(\text{AlO})=\frac{\Mu(\text{Al})}{\Mu(\text{AlO})}m(\text{AlO})=\\ \space\\ =\frac{27}{27+16}\cdot510=320\text{ g}.$$