Answer to Question #106447 in General Chemistry for Mila

Question #106447
Calculate how many grams of aluminum are contained in 510 grams Al O
1
Expert's answer
2020-03-24T14:02:29-0400

The aluminum (II) oxide is an interesting substance detected in stellar absorption spectra. Since the molar mass of aluminum is 27 g/mol and the molar mass of atomic oxygen is 16 g/mol, we can calculate what portion of mass accounts for aluminum:


ω(Al)=M(Al)M(AlO).\omega(\text{Al})=\frac{\Mu(\text{Al})}{\Mu(\text{AlO})}.

Therefore, the mass of aluminum contained in 510 g of the oxide is


m(Al)=ω(Al)m(AlO)=M(Al)M(AlO)m(AlO)= =2727+16510=320 g.m(\text{Al})=\omega(\text{Al})m(\text{AlO})=\frac{\Mu(\text{Al})}{\Mu(\text{AlO})}m(\text{AlO})=\\ \space\\ =\frac{27}{27+16}\cdot510=320\text{ g}.

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