Question

If you begin with 995 grams of ch4 and 2510 grams of h2o. How many grams of CO could you make from this reaction?

Answer 1

CH₄ + H₂O $\to$ CO + 3H₂

$n(CH_4)=m(CH_4)/M(CH_4)$

$n(CH_4)=995g/(16g/mole)=62.19 mole$

$n(H_2O)=m(H_2O)/M(H_2O)$

$n(H_2O)=2510g/(18g/mole)=139.44mole$

As we can see methane is in short supply.

According to the equation n(CH₄)= n(CO)

$m(CO)=62.19mole*28g/mole=1741.32g$

The answer is 1741.32 grams.