Answer to Question #106414 in General Chemistry for Whitney

Question

If you begin with 995 grams of ch4 and 2510 grams of h2o. How many grams of CO could you make from this reaction?

Answer 1

CH₄ + H₂O $\to$ CO + 3H₂

$n(CH_4)=m(CH_4)/M(CH_4)$

$n(CH_4)=995g/(16g/mole)=62.19 mole$

$n(H_2O)=m(H_2O)/M(H_2O)$

$n(H_2O)=2510g/(18g/mole)=139.44mole$

As we can see methane is in short supply.

According to the equation n(CH₄)= n(CO)

$m(CO)=62.19mole*28g/mole=1741.32g$

The answer is 1741.32 grams.