We have the equation
2H2 + O2 → 2H2O.
Calculate how many moles of H2 and O2 there are in 26.5 g of each substance:
"n_{H_2}=\\frac{m}{\\Mu_{H_2}}=\\frac{26.5}{2}=13.3\\text{ mol},\\\\\n\\space\\\\\nn_{O_2}=\\frac{m}{\\Mu_{O_2}}=\\frac{26.5}{32}=0.828\\text{ mol}."
We will calculate the reaction by oxygen because it has the smallest amount of substance. The amount of substance of water required is
"n_{H_2O}=2n_{O_2},\\\\\n\\space\n\\\\m_{H_2O}=n_{H_2O}\\cdot\\Mu_{H_2O}=\\\\=2n_{O_2}\\cdot\\Mu_{H_2O}=\\\\\n=2\\cdot0.828\\cdot18=29.8\\text{ g}."
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