Answer to Question #105918 in General Chemistry for jack

Question

How many grams of NaOH must be added to a 1.00L aqueous solution containing 2.00g of NiCl2 to fully remove the nickel (II) cation from the solution in the form of a Ni(OH)2 precipitate?

Answer 1

NiCl2 + 2NaOH = Ni(OH)2↓ + 2NaCl;

m(NiCl2)/M(NiCl2)=m(NaOH)/2*M(NaOH) ;

m(NaOH)=m(NiCl2)*2*M(NaOH)/M(NiCl2) ;

M(NaOH)=23+16+1=40;

M(NiCl2)=59+2*35.5=130;

m(NaOH)=2*2*40/130=1.23 gram;

Answer: 1.23 grams of NaOH are needed to fully remove the nickel (II) cation from the solution.