Answer to Question #104738 in General Chemistry for Kenzi K DeLong

Question

What is the percent yield of copper when 14g of Cu2O reacts with Cu2S and 12.6 grams of copper is recovered? Round to two decimal places and do not use a percent sign in your answer.

Answer 1

2Cu₂O+Cu₂S→6Cu+SO₂;

m(Cu₂O)/(2*M(Cu₂O))=m_theoretical(Cu)/(6*M(Cu));

m - mass;

M - molar mass;

m_theoretical=m(Cu₂O)*6*M(Cu)/2*M(Cu₂O) = 18.67 g ;

yield = actual yield/theoretical yield * 100= 67.49

Answer: 67.49