Answer to Question #104020 in General Chemistry for mya

Question

The rate constant for this first‑order reaction is 0.0760s^−1 at 400 degrees Celsius.

A⟶products

After how many seconds will 16.9%of the reactant remain?

Answer 1

Solution.

$k = \frac{1}{t} \times ln(\frac{С0}{С})$

С0 = 100 %

С = 16.9 %

$t = \frac{ln(\frac{Co}{C})}{k}$

t = 23.39 sec.

Answer:

t = 23.39 sec.