From First order rate law
T=(2.303/K) (log(a/(a-x)))
Where k=rate constant
T=time taken
a=initial concentration
a-x= reduced concentration
But for 1st order reaction the unit of the rate constant must be sec-1
Here the unit is M-1sec-1 which is the unit of 2nd order rate constant.
According to the question
T=(2.303/0.850)(log(0.710/0.290))
=1.053 sec required
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