9.35g Xg
C2H4 + 3O2 > 2CO2 + 2H2O
3*32g 2*18g
A: m(theor H2O) = X = 9.35*2*18/(3*32) = 3.506g.
B: η(H2O) = m(theor H2O)/m(pract H2O) = 2.63g/3.506g*100% = 75.01% = 75%.
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