Answer to Question #103769 in General Chemistry for Malachi McCarthy

Question

How many calories of heat were added to 246.9 g of water to raise its temperature from 25oC to 55oC?

Answer 1

We solve by the formula:

Q=c*m*ΔT=4.184 J/g °C*246.9 g*(55°C-25°C)=30 990.888 J=7.40 kcal

Q - absorbed heat

c- specific heat of water

ΔT - temperature change

The basis of the translation of quantities: 1 kcal = 4186.8 J