Solution.
m(H2O)=m(FePO4∗xH2O)−m(FePO4)m(H2O) = m(FePO4*xH2O) - m(FePO4)m(H2O)=m(FePO4∗xH2O)−m(FePO4)
m(H2O) = 8.1 g
n(H2O) = 0.45 mol
n(FePO4) = 0.11 mol
n(H2O):n(FePO4)=0.45:0.11=4.09:1.00n(H2O):n(FePO4) = 0.45:0.11 = 4.09:1.00n(H2O):n(FePO4)=0.45:0.11=4.09:1.00
FePO4×4H2OFePO4 \times 4H2OFePO4×4H2O
Answer:
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