Question

what volume of 6.0 M stock solution do you need to prepare 350 mL of a 1.5 M solution

Answer 1

Applying formula $M_1V_1=M_2V_2=M_3V_3.....$

where M is the molarity and V is the volume of the solution

substituting the values in the above formula we get

6*V₁=0.35*1.5

V₁=0.0875 litres

V₁ = 87.5 ml