Solution.
To find the number of ml of barium hydroxide through the law of equivalents, it is necessary to translate all molar concentrations to normal.
Cm(CH3COOH)=Cn(CH3COOH)
Cn(Ba(OH)2)=2×2.6=5.2 N
Because of this reaction:
2CH3COOH+Ba(OH)2=Ba(CH3COO)2+2H2O
Law of equivalents:
C1×V1=C2×V2
V(Ba(OH)2)=Cn(Ba(OH)2)Cn(CH3COOH)×V(CH3COOH)
V(Ba(OH)2) = 120.2 ml
Since the law of equivalent quantities of the starting materials are equal, then the amount of substance of salt equal to the amount of substance of a base or acid.
n(Ba(CH3COO)2)=5.2×0.1202=0.63 mol
The volume of the solution is equal to the sum of the volumes merged into the chemical reactor.
V=V(CH3COOH)+V(Ba(OH)2)
V = 245.2 ml
C(Ba(CH3COO)2)=Vn(Ba(CH3COO)2)
Cn(Ba(CH3COO)2) = 2.57 N
Answer:
V(Ba(OH)2) = 120.2 ml
Cn(Ba(CH3COO)2) = 2.57 N
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