Question #100491
Consider the reaction:
N2(g) + 3H2(g) → 2NH3(g)
Given an initial mass of 14.37 g N2, an excess of H2, and assuming that all of the reactant is converted to product(s), and none is lost, calculate the mass (g) of NH3 produced by the reaction.
N2(g) + 3H2(g) → 2NH3(g)
Given an initial mass of 14.37 g N2, an excess of H2, and assuming that all of the reactant is converted to product(s), and none is lost, calculate the mass (g) of NH3 produced by the reaction.
Expert's answer
N2(g) + 3H2(g) → 2NH3(g)
m(NH3)=14.37(g)*2*17(g/mol)/14(g/mol)*2=17.45(g)
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#340153 on Dec 2023
#340153 on Dec 2023