Answer to Question #100486 in General Chemistry for ely

General Chemistry

Question #100486

if i have 4 mola of gas at a pressure of 5.6 atm and a volume of 12 liters what is the temperature

Expert's answer

PV = nRT

P= 5.6 atm

V= 12litr

n= 4 mole

R = 0.082

T= PV/nR

= (5.6*12)/(4*0.082)

= 204.87 K

Therefore the Temperature is 204.87 K

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