The frequency of homozygous dominant individuals equals:
f(SS) = n(SS) / n(total) = 369 / 500 = 0.738
The frequency of homozygous recessive individuals equals:
f(SS) = n(SS) / n(total) = 16 / 500 = 0.032
From here, the frequency of heterozygous individuals equals:
f(2Ss) = 1 - 0.738 - 0.032 = 0.23
As a result:
2Ss = 0.23 and S + s = 1. From here:
2S(1-S) = 0.23
S2 - S + 0.115 = 0
S = 0.87
s = 1 - 0.87 = 0.13
Answer: 0.87 and 0.13
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