Question

How many grams of aluminum oxide are produced from the synthesis reaction of 8.7 g of Al with oxygen gas? 4Al + 3O2 -> 2Al2O3

Answer 1

4Al + 3O₂ -> 2Al₂O₃

M (Al) = 27 g/mol

M (Al₂O₃) = 101.96 g/mol

n (Al) = m/M = 8.7/27 = 0.32 mol

n (Al₂O₃) = 1/2 x n (Al) = 1/2 x 0.32 = 0.16 mol

m (Al₂O₃) = 0.16 x 101.96 = 16.4 g