Answer to Question #102223 in Biology for cass

Question

The molar concentration of a sugar solution in an open beaker has been determined to be 0.3M. Calculate the solute potential at 27 degrees. SHOW YOUR CALCULATIONS! Round your answer to the nearest hundredth. (Answers without shown work will not receive any credit)

Answer 1

Solute potential can be calculated by the following formula:

Ψ = - M × i × R ×T

where M - the molar concentration of the solute, i - the van't Hoff factor, the ratio of amount of particles in solution to amount of formula units, R - the ideal gas constant, T - is the absolute temperature.

As M = 0.3 M, i = 1 (sugar molecules do not dissociate), R = 8.314 (L·kPa)/(mol·K), and T = 27 °C = 300.15 K:

Ψ (sugar) = 0.3 M × 8.314 (L·kPa)/(mol·K) × 300.15 K = 748.63 kPa

Answer: 748.63 kPa