A test cross of F1 flies +a/+b produced the following offspring :
++/ab = 9
ab/ab = 9
+b/ab = 41
+a/ab = 41
What will be the distance between the linked genes and how?
(1) 82 cM
(2) 18 cM (cis)
(3) 20 cM
(4) 18 cM (trans)
1
Expert's answer
2015-09-09T05:21:05-0400
P: +a//+b X ab//ab Organism +a//+b produces the following types of gametes: Normal gametes: +a/, +b/ Gametes after crossover: ++/, ab/ Organism ab//ab produces the following types of gametes: ab/ G: +a/, +b/, ++/, ab/ X ab/ F1: +a//ab, +b//ab, ++//ab, ab//ab Results: ++/ab = 9 ab/ab = 9 +b/ab = 41 +a/ab = 41 According to the results the crossover percentage – 18% (9+9). The distance between the linked genes – 18 cM
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why is it trans and not cis
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