Using the Hardy-Weinberg Formula in studying population genetics, solve for:
a) genotype frequency of a heterozygous stag (male) and;
b) the probability of a doe (female) breeding with it.
The frequency of heterozygous individuals. Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).
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