Answer to Question #162488 in Genetics for punnet squares

Question

. A man who is homozygous dominant for blue hair marries a woman with green hair. They have four children. Predict the children’s’ genotypes and phenotypes

Answer 1

Let's assume that B is a blue hair allele and b is a green hair allele. As a result, the parental genotypes are:

Male - BB, possible gametes - B;

Female - bb, possible gametes - b.

The possible genotypes and phenotypes of their children are:

BB × bb

B × b

100 % Bb (blue hair).

As a result, all four children will have blue hair (genotype Bb)