Because black (B) is dominant over gray (d), a black cat may be homozygous (BB) or heterozygous (dd). The black female in this problem must be heterozygous (Bd) because her mother is gray (dd) and she must inherit one of her mother alleles. The gray male is homozygous (dd) because gray is recessive. Thus the cross is:
BB dd black female gray male Dd black Bb gray.
The probability of obtaining gray kittens is
"\\frac{8}{16}".
="\\frac{1} {2}"
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