Answer to Question #116408 in Genetics for R

Question

In reference to the Hardy-Weinberg equilibrium lab; Koi fish with the phenotype “White” is a result of a homozygous recessive allele.

If you have a Koi pond with 4 white fish (with a frequency of .25) and 12 orange fish (caused by the dominant allele and a frequency of .75), what would the frequency of the spotted fish phenotype for the population?

2pq = 0.5
q2 = 0.5
2pq= 0.25
2pq = 2.0

which is the correct option ?

Answer 1

According to the Hardy–Weinberg principle p² + 2pq + q² = 1

If q² = 0.25 and p² = 0.75, so 2pq = 0.