Question

in mice at one gene locus the dominant allele (B) produces a dark brown pigment; and recessive allele (b) produces a light brown or tan pigment. An independently assorting gene locus has dominant allele (C) the permits the production of all pigments. It's recessive allele (c) makes it impossible to produce any pigment at all. the pigments less condition is called "albino"

a) A homozygous bbcc albino mouse mates with a homozygous BBCC brown mouse. Assuming independent assortment, in what rations would the phenotypes and genotypes be expected in the F1 and f2 generations?

B) If an f1 mouse from part (a) above was backcrossed to its albino parent, what phenotypic and genotypic ratios would be expected?

Answer 1

Question #64125, Biology / Biochemistry

a) F1: phenotype – all offspring are dark brown

genotype – all offspring are double heterozygous BbCc

F2:

Dihybrid Cross

phenotype ration is $9:4:1$

9 – dark brown phenotype

4 – albino

3 – light brown phenotype

genotype ration is: $1:2:2:1:4:1:2:2:1$

b) P: ☐ BbCc × ☑ bbcc

phenotype ratio is $1:2:1$

1 – dark brown

2 – albino

1 – light brown

genotype ration is: $1:1:1:1$

1 – BbCc

1 – Bbcc

1 – bbCc

1 – bbcc

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