Answer to Question #304025 in Physics for skad

Question #304025

A force 16 N pushes the 2 blocks (m1 = 3kg and m2 = 5 kg) in a horizontal surface but doesn’t move. What is the static coefficient friction of the blocks?


1
Expert's answer
2022-03-01T15:18:06-0500

By definition, the static friction force is equal to the pushing force Ffr=F=16NF_{fr} = F = 16N. On the other hand,


Ffr=μNF_{fr} = \mu N

where μ\mu is the static friction coefficient, and N=mg=(3kg+5kg)9.8=78.4NN = mg = (3kg+ 5kg)\cdot 9.8 = 78.4N is the normal reaction. Thus, obtain:


μ=FN=16N78.4N0.2\mu = \dfrac{F}{N} = \dfrac{16N}{78.4N} \approx 0.2

Answer. 0.2.


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