Question #304014

A steel post 15 cm in diameter and 3 m long is placed vertically and is required

to support a load of 10,000 kg.

(a) What is the stress in the post?

(b) What is the strain in the post?


Expert's answer

Given:

l0=3 ml_0=3\:\rm m

d=0.15 md=0.15\:\rm m

m=10000 kgm=10000\:\rm kg

E=230∗109 PaE=230*10^9\:\rm Pa

(a) What is the stress in the post?

σ=FA=mgπd2/4=10000∗9.83.14∗0.152/4=5.55∗106 Pa\sigma=\frac{F}{A}=\frac{mg}{\pi d^2/4}\\= \frac{10000*9.8}{3.14*0.15^2/4}=5.55*10^6\:\rm Pa

(b) What is the strain in the post?

ε=σE=5.55∗106230∗109=2.4∗10−5\varepsilon=\frac{\sigma}{E}=\frac{5.55*10^6}{230*10^9}=2.4*10^{-5}


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