a solid conducting sphere with an area of 16m2 has total charge of 4"\\mu C." Determine the electric field through the Gaussian surface
The Gauss's law says
"\\Phi=\\oint EdA=\\frac{q}{\\epsilon_0}""\\Phi=\\frac{4*10^{-6}}{8.85*10^{-12}}=4.5*10^5\\:\\rm N\\cdot m^2\/C"
Comments
Leave a comment