3. A ball is thrown vertically upward with a speed of 30 ft/s from the edge of a cliff 50 ft above sea level with what velocity with it hit the water?
a. 32.2 ft/s b. 58.6 ft/s c. 64.2 ft/s d. 52.3 ft/s
The law of conservation of energy says
"\\frac{mv_i^2}{2}+mgh=\\frac{mv_f^2}{2}"Hence, the final velocity
"v_f=\\sqrt{v_i^2+2gh}\\\\=\\sqrt{30^2+2*32.17*50}=64.2\\:\\rm ft\/s"Answer: c. 64.2 ft/s
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