Question #301443

If in the process oof rubbing the lenses of the eyeglasses, 6.28 x 10^10 electrons were transferred,


a) what is the charge of the lenses and the nylon cloth?


b) what is the change in their masses?

Expert's answer

The charge of the lenses (glass) is positive


q1=eN=1.6×1019C×6.28×1010=1.00×108Cq_1=eN\\ =1.6\times 10^{-19}\:\rm C\times 6.28\times 10^{10}=1.00\times 10^{-8}\:\rm C

The charge of the nylon cloth is negative


q2=eN=1.6×1019C×6.28×1010=1.00×108Cq_2=-eN\\ =-1.6\times 10^{-19}\:\rm C\times 6.28\times 10^{10}=-1.00\times 10^{-8}\:\rm C


The change in mass

Δm=Nme=6.2810109.11031kg=5.711020kg\Delta m=Nm_e\\ =6.28*10^{10}*9.1*10^{-31}\:\rm kg=5.71*10^{-20}\: kg

The lenses lose, the nylon cloth gains.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS