Question

A wire with a mass of 64 g and 1 m long floats horizontally in magnetic field. If

B = 1.6x10^-2 T is at the direction perpendicular to the wire, calculate the value of current in the wire with the aid of a diagram.

Answer 1

Given:

$m=0.064\:\rm kg$

$l=1.0\:\rm m$

$B=0.016\:\rm T$

The wire equilibrium condition is given by

$$mg=BIl$$

The required current

$$I=\frac{mg}{Bl}=\rm \frac{0.064*9.8}{0.016*1.0}=39\: A$$