A copper road whose length at 70°c is 4.0m is heated to 10°c find it
Given:
"l_0=4.0\\;\\rm m"
"\\Delta T=30\\:\\rm K"
"\\alpha=17*10^{-6}\\:\\rm K^{-1}"
The thermal linear expansion is described by an equation
"\\Delta l=l_0\\alpha\\Delta T\\\\\n=\\rm4.0\\: m*17*10^{-6}\\:\\rm K^{-1}*30\\: K=0.002\\: m=2\\: mm"
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