Answer to Question #299801 in Physics for Joie

Question

2. Four charges. q, 5.00 x10'C. q-3.00 x C. q-2.00 x10°C. -6.00 x10 C, are situated at the corners of a square of side 4.00m. Find the potential at the center of the square?

Answer 1

Given:

$q_1=5.00*10^{-7}\:{\rm C},\quad q_2=-3.00*10^{-7}\:\rm C$

$q_3=-2.00*10^{-7}\:{\rm C},\quad q_4=6.00*10^{-7}\:\rm C$

$r=\frac{\sqrt{2}}{2}*4.00\:\rm m=2.83\: m$

The net potential at the center of square

$$V=V_1+V_2+V_3+V_4$$ $$V=\frac{k}{r}(q_1+q_2+q_3+q_4)$$ $$V=\frac{9*10^9}{2.83}(5.00-3.00-2.00+6.00)*10^{-7}=1910\:\rm V$$